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Algebra

Exponential growth and decay

Models any quantity that changes at a rate proportional to its size: populations, continuous interest, cooling, decay.

N=N0ekt
Doubling timet2=ln⁡2k
Growth factor formN=N0(1+r)t, k=ln⁡(1+r)

Calculator

The live calculator needs JavaScript. The worked example below shows the same steps it would.

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  • Doubling time ln 2 / k = 6.931
  • At t = 10: N = 135.91

What the symbols mean

N
the amount at time t
N0
the starting amount (at t = 0)
k
the continuous growth rate per unit time; positive for growth, negative for decay
t
the time elapsed, in the same units as k
e
Euler's number, about 2.71828

When to use it

Use it when a rate is given as "continuous" or when a quantity grows or shrinks by the same *percentage* each moment: bacteria, populations, radioactive material, a drug in the bloodstream. If the rate is applied once per period (yearly interest, say), use the growth-factor form or the compound interest formula.

Worked example

A colony of 500 bacteria grows continuously at k = 0.04 per hour. How many are there after t = 10 hours?

  1. Start from the formula.

    N=N0⁢ek⁢t
  2. Substitute N0 = 500, k = 0.04, t = 10 and work it out.

    N=500⁢e0.04·10
    =500⁢e0.4
    ≈745.912

Answer N ≈ 745.91, about 746 bacteria

Why it works

The equation dN/dt=kN (rate of change proportional to amount) has N=N0ekt as its solution. That is the property that makes e special: ex is its own derivative.

Common mistakes

  • Using a percentage as k: 4% per hour is k = 0.04, not 4.
  • Mixing time units: if k is per year, t must be in years.
  • Using ekt when the rate is per period (5% a year compounded yearly is 1.05t, i.e. k = ln 1.05 ≈ 0.04879).